Following is the graph between `log t_(1//2)` and `log a` (`a` initial concentration) for a given reaction at `27^(@)C`.

Find the order of reaction.

Following is the graph between log T_(50) and log a (a = initial concentration) for a given reaction at 27^(@)C . Hence, order is

Following is the graph between log T_(50) and log a ( a = initial concentration) for a given reaction at 27^(@)C . Hence order is

Following is the graph between log T_(50) and log a ( a = initial concentration) for a given reaction at 27^(@)C . Hence order is

Following is the graph between log t_(1//2) and log a ( a initial concentration) for a given reaction at 300K Find the order of reaction.

A graph between log t_((1)/(2)) and log a (abscissa), a being the initial concentration of A in the reaction For reaction Ato Product, the rate law is :

A graph between log t_((1)/(2)) and log a (abscissa), a being the initial concentration of A in the reaction For reaction Ato Product, the rate law is :

A graph between log t_((1)/(2)) and log a (abscissa), a being the initial concentration of A in the reaction For reaction Ato Product, the rate law is :

A graph between log t_((1)/(2)) and log a (abscissa), a being the initial concentration of A in the reaction For reaction Ato Product, the rate law is :