`(|x+2|-x)/x lt2`

If f(x)={{:((x-2)/(|x-2|)+a,x lt 2),(a+b,x=2),((x-2)/(|x-2|)+b,x gt 2):} is continuous at x = 2, then a+b=

Let f (x)= {{:(x ^(2),0lt x lt2),(2x-3, 2 le x lt3),(x+2, x ge3):} then the tuue equations:

Let f (x)= {{:(x ^(2),0lt x lt2),(2x-3, 2 le x lt3),(x+2, x ge3):} then the tuue equations:

Show that the function defined by f(x)=(3-2x), x lt2 and f(x)=3x-7, x geq 2 is not derivable at x=2

The fuction f(x) is defined as follows: f(x) ={(2x-3,x lt 2),(x-1, x ge 2):} Prove that f(x) is continuous x at =2.

The fuction f(x) is defined as follows: f(x) ={(2x-3,x lt 2),(x-1, x ge 2):} Prove that f(x) is continuous x at =2.

Solve for x, if sqrt(x^(2)-3x+2) lt x-2

Solve for x, if sqrt(x^(2)-3x+2) lt x-2