A particle starts from rest and moves with an angular acceleration of 3 ` rad //s^(2) ` in circle of radius 3 m . Its linear speed after 5 seconds will be

A particle starts with constant angular acceleration of "2 rad/s"^(2) in a circle of radius 4m. Find angle between net acceleration and radial acceleration after 2 s :-

A disc of radius 0.1 m starts from rest with an angular acceleration of 4.4 rad//s^(2) .Then linear velocity of the point on its after 5 s is

A particle is moving with angular acceleration of 1.2 rad//s^(2) on a circle of radius 1m. Finds its total acceleration (in m//s^(2) ) after rotating sqrt(6) rad. If its initial angular velocity is zero.

A disc of radius 0.1 m starts from rest with an angular acceleration of 4.4 rad//s^2 . Then linear velocity of the point on its circumference after 5 s is

The distance travelled by a particle starting from rest and moving with an acceleration 3 ms^-2 , in the 5th second is.

The distance travelled by a particle starting from rest and moving with an acceleration 4/3m/s2 ,in the third-second is

A particle moves along a circular path a radius 15 cm with a constant angular acceleration of 4 "rad/s"^(2). If the initial angular speed of the particle was 5 rad/s. Find its angular displacement in 5 seconds.

If a particle rotates along a circle of radius 3 m with an angular acceleration of (pi)/(2) "rad"//s^(2) starting from rest, then its average velocity over the time it covers quarter circle is :

A particle starts moving at t = 0 in a circle of radius R = 2m with constant angular acceleration of a - 3 "rad/sec"^(2) . Initial angular speed of the particle is 1 rad/sec. At time t_(0) the angle between the acceleration vector and the velocity vector of the particle is 37^(@) . What is the value of t_(0) ?

An object starting from rest travels with an acceleration of 5 m / s^2 . What will be its velocity after 3s?