When an electric cell drives current through load resistance, its back emf,

An electric cell is sending electric currents through a resistance of 10 Omega . IF a shunt of 1 Omega is connected with that resistance then the current through the 10 Omega resistance becomes half of the previous value.What is the resistance of the cell?IF the current through the shunt be 0.9A, then what will be the emf of the cell?

Acell of internal resistance r drives a current through an external resistance R . The power delivered by the cell to the external resistance is maximum when

A cell of internal resistance r drivers current through an external resistance R. The power delivered by the to the external resistance will be maximum when:

A cell of emf E and internal resistance ® is connected across an external resistance, R. The cell shall drive maximum current through the external resistance R only if

The cell drives current through a circuit when the circuit is closed. In a closed circuit the emf of the cell is

5When a cell of emf E and internal resistance r, is connected to the ends of a resistance R, then current through resistance is I. If the same cell is connected to the ends of a resistance R/2 then the current would be-

The value of an unknown resistance is found to be 8Omega when it is determined with the help of a wheatstone bridge by using known reistance 100Omega , 10Omega and 80 Omega . The emf of the electric cell used is 2 v and its internal resistance is 1.1Omega Determine the value of current flowing through the cell .

A cell of emf E and internal resistance r drives a current of 5 Ampere through an extenal resistance of 8 ohm. The current drops to 4 Ampere when the external resistance is increased to 10.1 ohm. Find the emf E and the internal resistance r of the cell.