5 14 Abeam of light is sent along the line x-y -1, which after refracting from the x-axis enters the opposite side tuming through 300 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is

A beam light is sent along the line x-y=1, which after refraction from the x-axis enters the opposite side by turning through 30^@ towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (2-sqrt(3))x-y=2+sqrt(3) (2+sqrt(3))x-y=2+sqrt(3) (2-sqrt(3))x+y=(2+sqrt(3)) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1, which after refracting from the x-axis enters the oppositi side by turining through 30^@ towards the normal at the point of incidence on the x-axis. Then the equation of the refracrted ray is

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.