What will be the capacity of a parallel-plate capacitor when the half of parallel space between the plates is filled by a material of dielectric constant `epsi_(r)` ? Assume that the capacity of the capacitor in air is C.

The space between the capacitor plates is filled with a dielectric of dielectric constant K. How will the capacity change ?

The Capacity of a parallel plate capacitor be comes 10 muF when air between the plates is re placed by a dielectric slab (k =2). What is the capacity of the capacitor with air in between the plates?

Consider a disconnected plate capacitor of capacity 10 muF with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in .The capacity of the capacitor changes to .

Consider a disconnected. Plate capacitor of capacity 10 mu with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in .The capacity of the capacitor changes to .

Consider a parallel plate capacitor of 10 muF (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4 , as shown in the figure. The capacity of the capacitor charges to

Consider a parallel plate capacitor of 10 muF (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4 , as shown in the figure. The capacity of the capacitor charges to