`._1H^2 + ._1H^2 to ._2He^4+Q`. In this reaction the masses of deuterium and helium atoms are 2.0141 u and 4.0024 u respectively. What is this process called, and what is the energy released Q , in MeV

Consider the reaction _1^2H+_1^2H=_2^4He+Q . Mass of the deuterium atom =2.0141u . Mass of helium atom =4.0024u . This is a nuclear………reaction in which the energy Q released is…………MeV.

Consider the reaction _1^2H+_1^2H=_2^4He+Q . Mass of the deuterium atom =2.0141u . Mass of helium atom =4.0024u . This is a nuclear………reaction in which the energy Q released is…………MeV.

The bombardment of Lithium with protons gives rise to the following reaction: ._3Li^7+._1H^1 to .2_He^4+.2_He^4+Q The atomic masses of lithium, hydrogen and helium are : 7.016u, 1.008u and 4.004u resp. Find the initial energy of each of alpha particle. Take 1a.m.u=931MeV .

Consider the nuclear reaction , ""_1H^2 + ""_1H^3 to ""_2He^4 + ""_0n^1 . If the binding energies of ""_1H^1, ""_1H^3 " and " ""_2He^4 are a, b and c respectively (in MeV), then the energy released in this reaction is

The nuclear reaction .^2H+.^2H rarr .^4 He (mass of deuteron = 2.0141 a.m.u and mass of He = 4.0024 a.m.u ) is

The nuclear reaction .^2H+.^2H rarr .^4 He (mass of deuteron = 2.0141 a.m.u and mass of He = 4.0024 a.m.u ) is

Bombardment of lithium with protons gives rise to the following reaction : ._3Li^7 + ._1H^1 to 2 (._2He^4)+Q . Find the Q-value of the reaction. The atomic masses of lithium, proton and helium are 7.016 u, 1.008 u and 4.004 u respectively.