The elimination of the arbitrary constant k from the equation `y=(x+k)e^(-x)` gives the differential equation

The elimination of the arbitrary constants A,B and C from y=A+Bx+Ce^(-x) leads to the differential equation.

What is the differential equation detected by the elimination of the arbitrary constant "K" from the equation y=(x+K)e^(-4)

Elimination of arbitrary constants A and B from y=(A)/(x)+B,xgt0 leads to the differential equation

In each of the following cases, from the differential equation by eliminating the arbitrary constants from the given equation: y=Ae^(-mx)+Be^(-mx) , A and B are arbitrary constants.

The differential equation by eliminating the arbitrary constant from the equation xy=ae^(x)+be^(-x)+x^(2) is xy_(2)+ky_(1)-xy=k then k=

from the differential equation by eliminating the arbitrary constants from the following equations : (1) y= e^(x) (A cos x + B sin x)

Form the differential equation by eliminating the arbitrary constant from the equation xy = ae^(x) + be^(-x) + x^(2)

Form the differential equation by eliminating the arbitrary constant from the equation y = a cos x + b sin x + x sin x