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For all real values of a and b lines (2a...

For all real values of a and b lines `(2a + b)x +(a +3b)y + (b-3a) =0 `and `mx+ 2y +6 =0 `are concurrent, then m is equal to (A) -2 (B) -3(C)-4 (D) -5

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`(2a+b)x+(a+3b)y+(b-3a) = 0`
`=>2ax+bx+ay+3by+b-3a= 0`
`=>a(2x+y-3)+b(x+3y+1)= 0`
`=>(2x+y-3)+b/a(x+3y+1) = 0`
Above equation represents equation of family of lines with `lambda = b/a`.
So, we can find intersection of these two lines.
`2x+y-3 = 0->(1)`
`x+3y+1 = 0->(2)`
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