Simplify the following fractions:
`(9g-6h)/(6g-4h)`

Simplify the following fractions: (21+6)/(7+6)

Classify the following reactions as C_2H_4(g) + H_2 rarr C_2H_6 (g)

Calculate the hest of reaction of the following reaction : C_(6)H_(12)O_(6(s)) + rarr 6CO_(2(g)) + 6H_(2)O_((g)) : Delta H = ?

Calculate standard free energy change from the free energy of formation data for the following reaction, C_(6)H_(6)(l)+(15)/(2)O_(2)(s)to 6CO_(2)(g)+3H_(2)O(g) . Delta_(f)G^(theta)[C_(6)H_(6)(l)]=172.8 kJ/mol Delta_(f)G^(theta)[CO_(2)(g)]=-394.4 kJ/mol Given that. Delta_(f)G^(theta)[CO_(2)(g)]=394.4 kJ/mol Delta_(r )G^(theta)[H_(2)O(l)]=-228.6 kJ/mol

Why does the following reaction occurs? XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(aq)toXeO_(3)(g)+F_(2)(g)+3H_(2)O(l)

Justify the following reaction is redox reaction 4NH_3(g) + 5O_2 (g) to 4NO (g) + 6H_2O (g)

Equilibrium constants for the following reactions at 1200 K are given : 2H_2O(g)hArr2H_2(g)+O_2(g):K_1=6.4xx10^(-8) 2CO(g)hArr2CO(g)+O_2(g):K_2=1.6xx10^(-6) The equilibrium constant for the reaction H_2(g)+CO_2(g)hArrCO(g)+H_2O(g) at 1200K will be-