If a triangle ABC, inscribed in a fixed circle, be slightly varied in such away as to have its vertices always on the circle, then show that `(d a)/(c a sA)+(d b)/(cosB)+(d c)/(cosC)=0.`

If a triangle ABC ,inscribed in a fixed circle,be slightly varied in such away as to have its vertices always on the circle,then show that (da)/(cas A)+(db)/(cos B)+(dc)/(cos C)=0

If a triangle ABC inscribed in a fixed circle be slightly varies in such a way as to have its varies aways on the circle, then show that (da)/(cosA)+(db)/(cos B)+(dc)/(cos c)= 0

If a triangle ABC inscribed in a fixed circle be slightly varied in such a way that its vertices are always on the circle, show that, (da)/(cosA) + (db)/(cosB) + (dc)/(cosC)= 0 .

ABC is a trangle whose sides are a units, b units and c units respectively and their corresponding opposite angles are A,B and C. If triangle ABC incribed in a fixed circle be slightly varied in such a way that its vertices are always on the circle, then the value of cos B cos C da + cos A cos C db + cos A cos B dc is -

If a, b, c are the sides of DeltaABC , inscribed in a given circle, then (deltaa)/(CosA)+(deltab)/(CosB)+(deltac)/(CosC)=

Delta ABC is not a right angled and is inscribed in a fixed circle. If a,A,b,B be slightly varied keeping c,C fixed then (deltaa)/(cosA)+(deltab)/(cosB)=

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(c sA)+(d b)/(cosB)=0

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(c sA)+(d b)/(cosB)=0

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(c sA)+(d b)/(cosB)=0

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(cosA)+(d b)/(cosB)=0