Home
Class 10
MATHS
Let ABCD be a square of side 2a. Find th...

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when (i) A coincides with the origin and AB and AD are along OX and OY respectively. (ii) The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively

Promotional Banner

Similar Questions

Explore conceptually related problems

ABCD is a square of side 2a. Taking the centre of the square as origin and axes parallel to the sides AB and AD. The coordinates of the vertices of the square are

ABCD is a square having length of a side 20 units. Taking the centre of the square as the origin and x and y axes parallel to AB and AD respectively, find the coordinates of A, B, C and D.

Taking AB, AD as axes, the coordiantes of the point C when ABCD is a square of side a is

The center of a square is at the origin and its one vertex is A(2,1) . Find the coordinates of the other vertices of the square.

The center of a square is at the origin and its one vertex is A(2,1). Find the coordinates of the other vertices of the square.

The center of a square is at the origin and its one vertex is A(2,1) . Find the coordinates of the other vertices of the square.

ABCD is a square 2a unit. Taking AB and AD as axes of coordinates, the equation to the circle which touches the sides of the square is

ABCD is a square whose side is a. Taking AB and AD as axes, find the equation of the circle circumscribing the square.

ABCD is a square with side a. If AB and AD are taken as coordiate axes. Then the equation of the circle circumseribing the square is.