Two identical magnets with a length `10cm` and weights `50gf` each are arragned freely with their like poles facing in a vertical glass tube. The upper magnet hangs in air above the lower one so that the distance between the nearest poles of the magnets is `3mm`. Determine the pole strength of the poles of these magnets.

Two identical magnetic with a length 10 cm and weight 50 g of each are arranged freely with their like poles facing in a inverted vertical glass tube. The upper magnet hangs in the air above the lower one so that the distance between the nearest pole of the magnet is 3mm. Pole strength of the poles of each magnet will be

Two identical bar magnets with a length 10cm and weigth 50 gm-weigth are arranged freely with their like poles facing in a inverted vertical glass tube. The upper magnet hangs in the air above the lower one so that the distance between the nearest pole of the magnet is 3 mm. Pole strength of the poles of each magnet will be

The distance between two poles of magnets is called as

The distance between two magnetic pole is doubled and the pole strength of each is halved, the force between them will be

The moment of a magnet is 3 xx 10^(-1)A m^(2) and the length of the magnet is 10cm. The pole strength of the magnet is (in A.m)