Velocity of particle of mass 2kg varies with time t accoridng to the equation `vecv=(2thati+4hatj)ms^(-1)`. Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

Velocity of a particle of mass 2kg varies with time t according to the equation vec(v)=(2thati+4hatj) m//s . Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

In the figure the variations of componets of acceleration of particles of mass 1kg is shown w.r.t. time. The initial velocity of the particle is vec(u)=(-3 hati+4hatj) m/s. the total work done by the resultant force on the particles in time intervals from t=0 to t=4 seconds is :

Velocity of a particle moving in a curvilinear path varies with time as v=(2t hat(i)+t^(2) hat(k))m//s . Here t is in second. At t=1 s

Velocity of a particle moving in a curvilinear path varies with time as v=(2t hat(i)+t^(2) hat(k))m//s . Here t is in second. At t=1 s

If velocity (in ms^(-1) ) varies with time as V = 5t, find the distance travelled by the particle in time interval of t = 2s to t = 4 s.

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) The velocity time graph of the particle is

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) The velocity time graph of the particle is

Angular position theta of a particle moving on a curvilinear path varies according to the equation theta=t^(3)-3t^(2)+4t-2 , where theta is in radians and time t is in seconds. What is its average angular acceleration in the time interval t=0s to t=2s?

Displacement of a particle of mass 2 kg varies with time as s=(2t^(2)-2t + 10)m . Find total work done on the particle in a time interval from t=0 to t=2s .

Displacement of a particle of mass 2 kg varies with time as s=(2t^(2)-2t + 10)m . Find total work done on the particle in a time interval from t=0 to t=2s .