If binomial coeffients of three consecutive terms of `(1 + x )^(n) ` are in H.P., then the maximum value of n, is

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ratio 5:10:14. Then n=

If the coefficients of three consecutive terms in the expansion of (1+x)^n are 45, 120 and 210 then the value of n is

If the coefficients of three consecutive terms in the expansion of (1+x)^n are 45, 120 and 210 then the value of n is

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ration 5 : 10 : 14 . Then n =

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ratio 5:10:14 . Then, n is equal to :