`i^(12)+i^(13)+i^(14)+i^(15)`

The conjugate of i^(13) + i^(14) + i^(15) + i^(16) is …………

i^(14)+i^(15)+i^(16)+i^(17)=

Write the following in the form x+iy: (i) i+i^(2)+i^(3)+i^(4) (ii) i^(4)+i^(8)+i^(12)+i^(16) (iii) i+i^(5)+i^(9)+i^(13) (iv) i^(9)+i^(10)+i^(11)+i^(12) .

Show that i^(15)+i^(17)+i^(19)+i^(21)+i^(24) is a real number.

Show that i^(15)+i^(17)+i^(19)+i^(21)+i^(24) is a real number.

Simplify the following: i^(4)+i^(8)+i^(12)+i^(16)

Let i^(2)=-1 , then (i^(10)-1/(i^(11)))+(i^(11)-1/(i^(12)))+(i^(12)-1/(i^(13)))+(i^(13)-1/(i^(14)))+(i^(14)+1/(i^(15))) is equal to a) -1+i b) -1-i c) 1+i d) -i

If (i^(4)+i^(9)+i^(26))/(2-i^(8)+i^(10)-i^(15))=A+i B then (A, B)=

Simplify [(i^(4)+i^(9)+i^(16))/(3-2i^(5)-i^(10)-i^(15))]^(10)

6i^(50) + 5i^(33) - 2i^(15) + 6i^(48) = 7i .