A cell of emf `E` and internal resistance `r` connected in the secondary gets balanced against length `l` of potentiometer wire. If a resistance `R` is connected in parallel with the cell, then the new balancing length for the cell will be

A cell of emf (E) and internal resistance (r) is balanced across (l) length of potentiometer wire. If another cell of emf 2E and internal resistance (2r) is connected in parallel to the first cell , then the balancing length will be

In an experiment on measurements of emf of a cell by a potentiometer , the balancing length for a cell of emf E and internal resistance r is found to be I.Now if another cell of emf E and internal resistance 2r is connected in parallel to the first cell and balancing length determined , then the balancing length will be: "],[" 1) "(l)/(2)],[" 2) "21],[" 3) "(1)/(2)l],[" 4) "1]

is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . If the resistance is connected across the cell e , the balancing length will

The balancing length on a potentiometer wire with a cell of emf 2V and internal resistance 1Omega connected in the secondary circuit with no load is 200cm . If a resistor of 19Omega is connected parallel to the cell, the balancing length

The e.m.f. of a cell is balanced by fall of potential along 281 cm of potentiometer wire. If a resistance of 8 Omega is connected across the cell , the balancing length is found to be 151 cm. Calculate internal resistance of a cell.

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

In the given figure, battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10Omega is connected in parallel with the battery then it balances on 50 cm length of the potentiometer wire then internal resistance r of the battery is

The e.m.f. of a standard cell balances across 150 cm length of a wire of potentiometer. When a resistance of 2Omega is connected as a shunt with the cell, the balance point is obtained at 100cm . The internal resistance of the cell is