If the rate of a reaction gets doubled as the temperature is increased from `27^@ " to " 37^@C`. Find the activation energy of reaction?

The specific rate constant of a particular reaction quadruples when temperature is changed from 27^@" to "47^@C . Find activation energy for the reaction.

The specific rate constant of a particular reaction quadruples when temperature is changed from 27^@" to "47^@C . Find activation energy for the reaction.

The specific rate constant for a reaction increases by a factor if the temperature is changed from 27^(@) C to 47^(@) C. Find the activation energy for the reaction. (R = 198 cal )

The rate constant of a reaction increases by 5% when its temperature is raised from 27^@c to 28^@c. The activation energy of the reaction is

Assertion (A) : Rate of reaction will be doubled, when temperature increased from 298 k to 308 k. Reason (R ): The activation energy of reaction decreases with increase in temperature.

The rate constant of a reaction is doubled when the temperature is raised from 298 K to 308 K. Calculate the activation energy.