`(3+5i)(2+6i)`

If i=sqrt(-1) , then (7+5i)(-2-6i)=

If x + iy = (3 + 5i)/(7-6i), they y =

If x +iy =(3+5i)/(7-6i) then y is equal to

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

If x+i y=(3+5i)/(7-6i), then y is A. 9/85 B. -9/(85) C. (53)/(85) D. none of these

Express the following in the form a + ib (2+ 5i)/(3-2i) + (2-5i)/(3 + 2i)

Show that ((19- 7i)/(9 + i))^(12) + ((20 - 5i)/(7 - 6i))^(12) is real.

Write the conjugate of the complex numbers (2+5i)(-4+6i)

Find the modulus of ((1+3i)(2-5i))/((2-sqrt(6i))(-3+2sqrt(5i)))