किसी `triangleABC` में सबसे बड़ा कोण ज्ञात करे यदि
`a = 2, b = sqrt(6), c = sqrt(3) -1`

In DeltaABC, if a= 2, b= sqrt(6) and c= sqrt(3)+1 then A=

In a DeltaABC if a = 2, b=sqrt(6),c=sqrt(3)+1 , then cos A=

In a DeltaABC if a = 2, b=sqrt(6),c=sqrt(3)+1 , then cos A=

यदि triangleABC में (If इन triangleABC), a = (1)/(sqrt(6)-sqrt(2)), b = (1)/(sqrt(6)+sqrt(2)), C = 60^(@) तो सिद्ध कीजिए कि (Prove that) c = (sqrt(4))/(2) .

In triangleABC, angleA=60, b = sqrt(3)+1 and c = sqrt(3)-1 then the value of tan ((B-C)/2) is-

If, in triangleABC, a= sqrt(2), b= sqrt(3), c = sqrt(5) , then the area of triangleABC is

(3-sqrt(6))/(3+2sqrt(6))=a sqrt(6)-b

In triangleABC , if a=sqrt(3)+1, b=sqrt(3)-1 and angleC=60^(@) , then c=

The value of a,b,c if [(0,2b,c),(a,b,-c),(a,-b,c)] is orthogonal are a) a= pm (1)/(sqrt(2)), b = pm (1)/(sqrt(6)) , c = pm (1)/(sqrt(3)) b) a = pm (1)/(sqrt(2)), b = pm (1)/(sqrt(3)), = pm (1)/(sqrt(6)) c) a = pm (1)/(sqrt(6)) , b = pm (1)/(sqrt(2)), c = pm (1)/(sqrt(3)) d) a = pm (1)/(sqrt(3)) , b = pm (1)/(sqrt(2)) , c = pm (1)/(sqrt(6))

In triangleABC, if a=2, b=1, c=sqrt(3) , then angleA=