A point on a parabola `y^2=4a x ,` the foot of the perpendicular from it upon the directrix, and the focus are the vertices of an equilateral triangle. The focal distance of the point is equal to `a/2` (b) `a` (c) `2a` (d) `4a`

A point P on the parabola y^(2)=4x , the foot of the perpendicular from it upon the directrix and the focus are the vertices of an equilateral triangle. If the area of the equilateral triangle is beta sq. units, then the value of beta^(2) is

A point P on the parabola y^(2)=4x , the foot of the perpendicular from it upon the directrix and the focus are the vertices of an equilateral triangle. If the area of the equilateral triangle is beta sq. units, then the value of beta^(2) is

If a point P on y^2=4x , the foot of the perpendicular from P on the directrix and the focus form an equilateral traingle , then the coordinates of P may be

If a point P on y^2=4x , the foot of the perpendicular from P on the directrix and the focus form an equilateral traingle , then the coordinates of P may be

If a point P on y^2x , the foot of the perpendicular from P on the directrix and the focus form an equilateral traingle , then the coordinates of P may be

If a point P on y^2x , the foot of the perpendicular from P on the directrix and the focus form an equilateral traingle , then the coordinates of P may be

The foot of the perpendicular from the point (2,4) upon x+y=4 is

Find the foot of the perpendicular from the point (2,4) upon x+y=1.

Find the foot of the perpendicular from the point (2,4) upon x+y=1

Find the foot of the perpendicular from the point (2,4) upon x+y=1.