In a `!ABC` bisector of angle C meets the side AB at D and circumcricle at E. The maximum value of CD . DE is equal to

In DeltaABC with fixed length of BC , the internal bisector of angle C meets the side AB at D and the circumcircle at E . The maximum value of CD xx DE is

In a triangle ABC bisector of lfloor C meets the side AB at D and circum circle at E. The maximum value of CD×DE is

In DeltaABC with fixed length of BC , the internal bisector of angle C meets the side AB at D and meet the circumcircle at E. The maximum value of CD xx DE is

In Delta ABC with fixed length of BC, the internal bisector of angle C meets the side AB at D and meet the circumcircle at E. The maximum value of CD xx DE is

In Triangle A B C with fixed length of B C , the internal bisector of angle C meets the side A B a tD and the circumcircle at E . The maximum value of C D×D E is c^2 (b) (c^2)/2 (c) (c^2)/4 (d) none of these

In A B C with fixed length of B C , the internal bisector of angle C meets the side A Ba tD and the circumcircle at E . The maximum value of C D.D E is c^2 (b) (c^2)/2 (c) (c^2)/4 (d) none of these

In a triangle ABC, angle bisector of angle BAC cut the side BC at D and meet the circumcircle of Delta ABC at E , then find AB .AC+DE. AE.

In a triangle ABC, angle bisector of angleBAC cut the side BC at D and meet the circumcircle of DeltaABC at E. If AC = 4 cm, AD = 5 cm, DE = 3 cm. Find the length of AB.