[" Let "f(x)=(x^(2)-9x+20)/(x-[x])" (where "[x]" is the greatest "],[" integer not greater than "x" ).Then "]

Let f(x)=(x^2-9x+20)/(x-[x]) (where [x] is the greatest integer not greater than xdot Then (A) ("lim")_(x->5)f(x)=1 (B) ("lim")_(x->5)f(x)=0 (C) ("lim")_(x->5)f(x) does not exist. (D)none of these

Let f(x)=(x^2-9x+20)/(x-[x]) (where [x] is the greatest integer not greater than xdot Then (A) ("lim")_(x->5)f(x)=1 (B) ("lim")_(x->5)f(x)=0 (C) ("lim")_(x->5)f(x) does not exist. (D)none of these

Let f(x)=(x^2-9x+20)/(x-[x]) (where [x] is the greatest integer not greater than xdot Then (a) ("lim")_(xvec5)f(x)=1 (b) ("lim")_(xvec5)f(x)=0 (c) ("lim")_(xvec5)f(x)does not exist (d)none of these

Let f(x)=(x^(2)-9x+20)/(x-[x]) where [x] denotes greatest integer less than or equal to x), then

If f(x)=[x] , where [x] is the greatest integer not greater than x, in (-4, 4), then f(x) is

If f(x)=[x] , where [x] is the greatest integer not greater than x, then f'( 1^(+) )= . . .

int_(0)^(pi//2) (x-[sin x]) dx = ___ (where [x] = greatest integer not greater than x)

Let f(x) = (x^2-9x+20)/(x-[x]) where [x] denotes greatest integer less than or equal to x ), then

Let f(x) = (x^2-9x+20)/(x-[x]) where [x] denotes greatest integer less than or equal to x ), then

If f(x) = [x] ,where x is the greatest integer not greater than x,-2 le xle2 , then at x= 1