Calculate the rate of increment of the thickness of the layer of ice on a lake when the thickness of is `20cm` and the air temperature is `-40^(@)C`. Thermal conductivity of ice `=1.68Ks^(-1)m^(-1)K^(-1)` , density of ice `920kgm^(-3)` and latent heat capacity of ice `=336xx10^(3)Jkg^(-1)K^(-1)`.

Calculate the rate of increment of the thickness of ice layer on a lake when thickness of ice is 10 cm and the air temperature is -5^(@) C . If thermal conductivity of ice is 0.008 cal "cm"^(-1) "s"^(-1)°"C"^(-1) , density of ice is 0.91 xx 10^(3) "kg m"^(-3) and latent heat is 79.8 cal "gm"^(-1) . How long will it take the layer to become 10.1 cm ?

At what rate a layer of ice will be formed if the surrounding temperature is at -10^(@)C ? Thermal conductivity of ice =1.6Wm^(-1)K^(-1) . Initial thickness of ice is 1mm

The thickness of ice on a Jake is 6 cm and the temperature of air is - 10^(@) C . At what rate is the thickness of ice increasing ? Thermal conductivity of ice = 2 "Wm"^(-1) "K"^(-1) . Density of ice = 920 "kg m"^(3) , specific latent heat of ice = 336 "KJ kg"^(-1)

The thickness of ice in a lake is 10 cm and its temperature is -10^(0)C . The thermal conductivity of ice = 0.004 cal cm^(-1)" sec"^(-1)""^(0)C^(-1) . Density of ice = 0.92 g/cc, latent heat of ice = 80 cal/g. The time taken for thickness of ice to be doubled is

What does it mean to say that latent heat of ice equals 3.36xx10^5Jkg^(-1) ?

The thickness of ice in a lake is 5cm and the atmospheric temperature is 10^(@)C Calculate the time rquired for the thickness of ice to grow to 7cm Therml conductivity for ice =4 xx 10^(-3) cal cm^(-1) s^(-1) c^(-10 density of ice =0.92 g //cm^(3) and latent heat of fusion of ice =80 cal//g .

A lake surface is exposed to an atmosphere where the temperature is lt 0^(@)C . If the thickness of the ice layer formed on the surface grows form 2cm to 4cm in 1 hour. The atmospheric temperature, T_(a) will be- (Thermal conductivity of ice K = 4 xx 10^(-3) cal//cm//s//.^(@)C , density of ice = 0.9 gm//ice. Latent heat of fustion of ice = 80 cal//m . Neglect the change of density during the state change. Assume that the water below the ice has 0^(@) temperature every where)

A lake surface is exposed to an atmosphere where the temperature is lt 0^(@)C . If the thickness of the ice layer formed on the surface grows form 2cm to 4cm in 1 hour. The atmospheric temperature, T_(a) will be- (Thermal conductivity of ice K = 4 xx 10^(-3) cal//cm//s//.^(@)C , density of ice = 0.9 gm//ice. Latent heat of fustion of ice = 80 cal//m . Neglect the change of density during the state change. Assume that the water below the ice has 0^(@) temperature every where)

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)