In the given circuit, if the potential difference across the internal resistance `r_1` is equal to E, then the resistance R is equal to:

If the potential difference across the internal resistance r_1 is equal to the emf E of the battery, then

If the potential difference across the internal resistance r_(1) is equal to the emf E of the battery, then

Two cells of internal resistance r_1 and r_2 and of same emf are connected in series across a resistor of resistance R. If the terminal potential difference across the call of internal resistance r_1 is zero , then the value of R is

According to this diagram , the potential difference across the terminals is ( internal resistance of cell =r)

According to this diagram , the potential difference across the terminals is ( internal resistance of cell =r)

In a network as shown in the figure , the potential difference across the resistance 2 R is (the cell has emf E - volt and no internal resistance )

Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R_1 and R_2(R_1gtR_1) . if the potential difference across the source having internal resistance R_2 is zero, then find vlaue of R.

In a network as shown in the figure the potential difference across the resistance 2R is (the cell has an emf of E and has no internal resistance):

In a network as shown in the figure the potential difference across the resistance 2R is (the cell has an emf of E and has no internal resistance):