[" Q.22.A steel wire of cross-sectional area "1mm^(2)" is stretched by "10N" .Find the "],[" lateral strain produced in the wire.[Given-Y steel "=2times10^(14)N/m^(2),d=0.291]]

A steel wire having cross-sectional area 2 mm^(2) is stretched by 20 N. Find the lateral strain produced in the wire

A steel wire having cross - sectional area 2 mm^ 2 is stretched by 10 N. Find the lateral strain produced in the wire. (Given : Y for steel = 2xx 10 ^ (11) N//m^ 2 Poisson 's ratio sigma = 0. 29 )

A steel wire having cross sectional area 1.2mm^2 is stretched by a force of 120N. If a lateral strain of 1.455 mm is produced in the wire, calculate the Poisson’s ratio.

A steel wire having crosssectional area 1.2 mm2 isstretched by a force of 120 N. If a lateral strain of 1.455 xx 10^-4 is produced in the wire, calculate the Poisson's ratio. (Y for steel = 2 xx 10^11 N//(m^2)

A 1 m long steel wire of cross-sectional area 1 mm^(2) is extended 1 mm. If Y = 2 xx 10^(11) Nm^(-2) , then the work done is

A steel wire having cross-sectional area 1.5 mm^(2) when stretched by a load produces a lateral strain 1.5 xx 10^(-5) . Calculate the mass attached to the wire. ( Y_("steel") = 2xx 10^(11) N//m^(2) , Poisson's ration sigma = 0.291, g = 9.8 m//s^(2) )

A steel wire of diameter 1 mm, and length 2 m is stretched by applying a force of 2.2 kg wt. the extension produced in the wire is

When a copper wire of area of cross section 1 mm^(2) is stretched by a force of 10N. Then the work done per unit volume in stretching the wire is (Y=1.2xx10^(11)Nm^(-2))

A unifrom steel wire of length 6 m and area of cross section 2 mm^(2) is elastically strectched through 3 mm. Calculate the energy stored in the wire. [Y_("steel") = 2xx 10^(11) N//m^(2)]