For an elementary reaction `2A+B rarr A_(2)B` if the volume of vessel is quickly reduced to half of it's original volume then rate of reaction will `:`

For an elementary reaction. A + 2B rightarrow C if volume of the vessel is reduced to 1/3 of its original volume the rate of the reaction will

For a reaction A+ B rarr products, rate law expression for rate , r=K[A][B]^2 . If the volume of the container is reduced to half of its original volume, the rate of reaction will become

In the given elementary reaction 2A + B to A_2B , if the concentration of A is doubled and that of B is halved, then the rate of the reaction will:

2A(g)+B(g)rarrC(g) is a gaseous elementary reaction , the rate of which is found to be r " mol. L"^(-1).s^(-1) . If the volume of the reaction system is suddenly reduced to 1/4th of its original volume , then the rate of the reaction will be -

For the reaction A + B to products, rate low expression for rate = k[A][B]^(2) . If the volume of the vessel is reduced to 1/3 of its original volume then what will be the effect on the rate of reaction?

In a gaseous reaction 2P + Qrarr Products : Rate =k [P]^(2) [Q] The volume of the reaction vessel is suddenly reduced to half of its initial volume . The rate of eaction as compared to original rate becomes :

Following reaction takes place in single step. 2NO(g) + O_2(g) to 2NO_2(g) . How will the rate of the reaction change if the volume of the vessel is reduced to one third of its original volume? Will there be any change in the order of the reaction with the reduced volume?

For reaction : H_(2)(h)+I_(2)(g) hArr 2HI(g) at certain temperature, the value of equilibrium constant is 50 . If the volume of the vessel is reduced to half of its original volume, the value of new equilibrium constant will be

For reaction : H_(2)(h)+I_(2)(g) hArr 2HI(g) at certain temperature, the value of equilibrium constant is 50 . If the volume of the vessel is reduced to half of its original volume, the value of new equilibrium constant will be