In the following equilibria
`I:A+2B hArr C, K_(eq)=K_(1)`
`II: C+DhArr 3A, K_(eq)=K_(2)`
`III, 6B+D hArr 2C, K_(eq)=K_(3)`
Hence,

The following equilibria are given N_2+3H_2 harr 2NH_3 , K_c=K_1 , N_2+O_2 harr 2NO, k_c=K_2 , H_2+1/2 O_2 harr H_2O, K_C = K_3 The equilibrium constant of the reaction. 2NH_3+5/2 O_2 harr 2NO+3H_2O in the terms of K_1,K_2 and K_3 is

Consider the following equilibrium reactions at 25^oC , A(g)+3B(g)hArr2C(g),K_(eq)=x A(g)+D(g)hArr2E(g),K_(eq)=y B(g)+D(g)hArrF(g),K_(eq)=z then the value of equilibrium constant for the reaction 2C+4DhArr2E+3F , at 25^oC is

Given i) A harr B+C K_(eq)(1) ii) B+C harr P K_(eq)(2) then K_(eq) for reaction Aharrp is

Given i) A harr B+C K_(eq)(1) ii) B+C harr P K_(eq)(2) then K_(eq) for reaction Aharrp is

For the reactions A hArr B, K_(c ) =1 B hArr C, K_(c)=2 C hArr D, K_(c)=3 K_(c) for the reaction A hArr D is

The following equilibrium are given below, A_2 + 3B_2 hArr 2AB_3 ....K_1 A_2 + C_2 hArr 2AC ....K_2 B_2 + 1/2C_2 hArr B_2C ....K_3 The equilibrium constant of the reaction 2AB_3 + 5/2C_2 hArr 2AC + 3B_2C , in terms of K_1, K_2 , and K_3 is

The following equilibria are given by : N_(2)+3H_(2) hArr 2NH_(3), K_(1) N_(2)+O_(2) hArr 2NO,K_(2) H_(2)+(1)/(2)O_(2) hArr H_(2)O, K_(3) The equilibrium constant of the reaction 2NH_(3)+(5)/(2)O_(2)hArr 2NO +3H_(2)O in terms of K_(1) , K_(2) and K_(3) is

The following equilibria are given by : N_(2)+3H_(2) hArr 2NH_(3), K_(1) N_(2)+O_(2) hArr 2NO,K_(2) H_(2)+(1)/(2)O_(2) hArr H_(2)O, K_(3) The equilibrium constant of the reaction 2NH_(3)+(5)/(2)O_(2)hArr 2NO +3H_(2)O in terms of K_(1) , K_(2) and K_(3) is