`0.98g` of the chloroplatinate salt of some diaacidic base when ignited left `0.39g` of platinum as residue. What is the molecular mass of the base ? (At mass of `Pt = 195)` .

0.984 g of a chloroplatinate salt of a diacid base on ignition gave 0.39 g of platinum. Find the molecular mass of the base.

1.9g of the chloroplatinate of a diacid base when ignited left 0.75g of Pt. Calculate the molecular mass of the base. (Atomic mass of Pt is 195)

0.400 g of chloroplatinate salt of a monoacid base on ignition gave 0.125 g of platinum. Find the molecular mass of the base.

0.49 gm of chloroplatinate of a diacidic base gave on ingintion 0.195 gm of platinum. Calculate the molecular mass of the base.

0.96g chloroplatinate of a diacid base when ingnited gave 0.32 g platinum. The molecular mass of the base is [AW of Pt = 195]

An organic base is tetraacidic. If from every 10gm of the chloroplatinate salt of the base 3.9 gm of the residue of platinum is obtained, then what will be the molecualr mass of the base? [Pt = 195]