The solution of `sin 2 theta + cos 2theta + sin theta + cos theta + 1 =0` in the first quadrant is

The solution set of sin 2theta - cos 2theta - sin theta + cos theta = 0 is

The solution of sin2 theta+cos2 theta+sin theta+cos theta+1=0 in first quadrant is (n in1)

((sin theta+cos theta)^(2)-1)/(sin theta*cos theta)

cos^(2)theta-sin theta.cos theta-(1)/(2)=0

cos^(2)theta-sin theta*cos theta-(1)/(2)=0

cos^(2)theta-sin theta*cos theta-(1)/(2)=0

cos^(2)theta-sin theta*cos theta-(1)/(2)=0

cos^(2)theta-sin theta*cos theta-(1)/(2)=0

If 0 lt theta lt pi/2 , the solution of the equation sin theta - 3 sin 2 theta + sin 3 theta = cos theta - 3 cos 2 theta + cos 3 theta is

Prove that, (1 + sin 2 theta - cos 2 theta)/(sin theta + cos theta)= 2 sin theta