Assertion : `Cr^(2+)` is reducing and `Mn^(3+)` is oxidising.
Reason : `Cr^(2+)` and `Mn^(3+)` have `d^4` configuration.

Assertion :- Cr^(+2) is a reducing agent and Mn^(+3) is oxidising agent. Reason :- Mn^(+3) has d^(5) configuration.

Assertion :- Cr^(+2) is a reducing agent and Mn^(+3) is oxidising agent. Reason :- Mn^(+3) has d^(5) configuration.

Which of the following statement are correct about Cr^(2+) (Z = 24) and Mn^(3+) (Z = 25) ? (i) Cr^(2+) is a reducing agent (ii) Mn^(3+) is an oxidizing agent (iii) Both Cr^(2+) and Mn^(3+) exhibit d^(4) configuration (iv) When Cr^(2+) is used as a reducing agent, the chromium ion attains d^(5) electronic configuration

Which of the following statement are correct about Cr^(2+) (Z = 24) and Mn^(3+) (Z = 25) ? (i) Cr^(2+) is a reducing agent (ii) Mn^(3+) is an oxidizing agent (iii) Both Cr^(2+) and Mn^(3+) exhibit d^(4) configuration (iv) When Cr^(2+) is used as a reducing agent, the chromium ion attains d^(5) electronic configuration

Account for the following: (i) Transition elements exhibit higher enthalpies of atomisation. (ii) Cr^(2+) is reducing and Mn^(3+) is oxidising when both have d^4 configuration.

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?