`[(2^(2020)+1)/(2^(2018)+1)] + [(3^(2020)+1)/(3^(2018)+1)] + [(4^(2020)+1)/(4^(2018)+1)] + [(5^(2020)+1)/(5^(2018)+1)] + [(6^(2020)+1)/(6^(2018)+1)]`

If omega!=1 is a complex cube root of unity, then prove that [{:(1+2omega^(2017)+omega^(2018)," "omega^(2018),1),(1,1+2omega^(2018)+omega^(2017),omega^(2017)),(omega^(2017),omega^(2018),2+2omega^(2017)+omega^(2018)):}] is singular

If f(x)=(x)/(x+1) ,Which of the following is/are CORRECT. (A) f(f(2020))=(2020)/(4041) (B) f(f(f(2020)))=(2020)/(8081) (C) f(f(f(f(2020))))=(2020)/(2321) (D) f(f(f(f(f(2020)))))=(2020)/(10101)

If f(x)=(x)/(x+1) ,Which of the following is/are CORRECT. (A) f(f(2020))=(2020)/(4041) (B) f(f(f(2020)))=(2020)/(8081) (C) f(f(f(f(2020))))=(2020)/(2321) (D) f(f(f(f(f(2020)))))=(2020)/(10101)

[(1,0,0),(0,1,1),(1,0,0)]=A then A^(2025)-A^(2020)=

The remainder when the determinant |[2014^(2014),2015^(2015),2016^(2016)],[(2017^(2017),2018^(2018),2019^(2019)],[2020^(2020),2021^(2021),2022^(2022)]| is divided by 5 is-

The coefficient of x^(2017) in sum_(r = 0)^(2020)2020C_(r)(x-2018)^(2020-r)(2017)^(r) is

If (1)(2020)+(2)(2019)+(3)(2018)+…….+(2020)(1)=2020xx2021xxk, then the value of (k)/(100) is equal to

If f(x)=(4^(x))/((4^(x)+2)) and f((1)/(2020))+f((2)/(2020))+...+f((2019)/(2020))=1010+k then the value of k is

Let A = ({:(1,0,0),(0,1,1),(1,0,0):}) . Then A^(2025) - A^(2020) is equal to :