In YDSE, a source of light was used which emits a bichromatic beam. The two colours had wavelengths 800 nm and 400 nm each of intensity `I_0`. Find the maximum intensity which can be present at any point on the screen

A source simultaneously emitting light at two wavelengths 400 nm and 800 nm is used in the Young's double slit experiment. If the intensity of light at the slit for each wavelength is I_0 , then the maximum intensity that can be observed at any point on the screen is

Two coherent sources of intensities I_0 each produce minimum intensity of zero then the maximum intensity they can produce by interference is?

Two incoherent sources of light emitting light of intensity I_(0) and 3I_(0) interfere in a medium. Then the resultant intensity at any point will be

In a YDSE, the separation between slits is 2 mm where as the distance of screen from the plane of slits is 2.5 m . Light of wavelengths in the range 200-800 nm is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at 1 mm from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.

Two incoherent sources of light emitting light of intensity I_(0) and 3I_(0) interfere in a medium. Calculate, the resultant intensity at any point.