A 0.1 molal aqueous solution of `CuSO_4.5H_2O` at 1bar pressure. find the new boiling point (`K_b` value of water 0.512)

The boiling point (in ""^@ C) of 0.1 molal aqueous solution of CuSO_4.5H_2 O at 1 bar is closest to: [Given: Ebullioscopic (molal boiling point elevation) constant of water, K_b = 0.512 K Kg mol^(–1) ] :-

The boiling point (in ""^@C ) of 0.1 molal aqueous solution of CuSO_4. 5H_2O at 1 bar is closest to : [Given : Ebullioscopic (molal boiling point elevation) constant of water, K_b = 0.512 K Kg mol^(-1) ]

Out of 0.1 molal aqueous solution of glucose and 0.1 molal aqueous solution of KCl, which one will have higher boiling point and why?

Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. K_(b) for water is 0.512 K kg mol^(-1)

0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )

0.1 molal aqueous solution of glucose boils at 100.16 ""^(@)C . The boiling point of 0.5 molal aqueous solution of glucose will be ______.