[" For any positive integer "n" ,let "],[f(n)=(4n+sqrt(4n^(2)-1))/(sqrt(2n+1)+sqrt(2n-1))," then "]

For any positive n, let f(n)=(4n+sqrt(4n^(2)-1))/(sqrt(2n+1)+sqrt(2n-1)) . Then ((Sigma_(k=1)^(40)f(k))/(100)) is equal to

For any positive n, let f(n)=(4n+sqrt(4n^(2)-1))/(sqrt(2n+1)+sqrt(2n-1)) . Then ((Sigma_(k=1)^(40)f(k))/(100)) is equal to

lim_(n rarr4)(sqrt(2n+1)-3)/(sqrt(n-1)-sqrt(2))

If n is a positive integer , then (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is -

If n is a positive interger,them (sqrt(5)+1)^(2n+1)-(sqrt(5)-1)^(2n-1) is

If n is a positive integer, then: (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is:

If n is a positive integer, then (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is

For any integer n, the argument of ((sqrt3+i)^(4n+1))/((1-isqrt3)^(4n))