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4Zn +10HNO(3) to 4Zn(NO(3))(2) +NH(4)NO(...

`4Zn +10HNO_(3) to 4Zn(NO_(3))_(2) +NH_(4)NO_(3)+3H_(2)O`.
In this reaction one mole of `HNO_(3)` is reduced by

A

32g Zn

B

64g Zn

C

128g Zn

D

26g Zn

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