If `[PtCl_6]^(x-)` follows the Sidgwick rule of stability, what is the oxidation state of Pt and complex ?

Explanation

`[PtCl_6]^(x-)` following Sidgwick rule of stability ,thus EAN of Pt is to be equal to the atmic number of nearest inert gas 86(Rn). Let the oxidation state of platinumin `[PtCl_6]^(x-)` complex ion is y
`y + 6(-1) = -x (or) y = 6 - x`
`86 = 78 - (6-x) + 2xx 6 = 78 - 6 + x + 12 , x = 2`
Oxidation state of platinum forming the complex `=6 -x = 6-2 = +4`
Oxidation state of the complex = -2