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Why hexaquamanganese(II)ion contains fiv...

Why hexaquamanganese(II)ion contains five unpaired electrons, while the hexacyno manganese (II)ion contains only one unpaired electron ?

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`H_2O` is a weak field ligand and `CN^(-)` is a strong field ligand. Thus in `[Mn(H_2O)_6]^(2+)` , pairing of unpaired electrons is not possible and it possesses five unpaired electrons.
In `[Mn(CN)_6]^(4-)` pairing of four unpaired electrons takes place and it possesses one unpaired electron.
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Valence bond theory successfully explains the magnetic behaviour of complexes. The substances which contains unpaired electrons are paramagnetic and paramagnetic character increases as the number of unpaired electrons increases. Magnetic moment of a complex can be determined experimentally and by using formula sqrt(n(n+2)) and we can determine the number of unpaired electrons in it. This information is important in writing electronic structure of complex which in turn also useful in deciding the geometry of complex. The magnetic moment of complexes given below are in the order : {:(Ni(CO)_(4),[Mn(CN)_(6)]),("(I)","(II)"),([Cr(NH_(3))_(6)]^(3+),[CoF_(6)]^(3+)),("(I)","(II)"):}

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