If the point `(2 , alpha , beta) ` lies on the plane which passes through the points `(3,4,2) and (7,0,6)` and is perpendicular to the plane `2x-5y=15,` then `2 alpha - 3 beta` is equal to:

Find the equation of the plane through the points A(3,4,2) and B(7,0,6) and perpendicular to the plane 2x-5y=15 . Hint: The given plane is 2x-5y+0z=15 .

Consider the plane passing through the points A(2,2,1),B(3,4,2) and C(7,0,6) Which one of the following points lies on the plane

If a point (alpha, beta) lies on the circle x^(2)+y^(2)=1 , then the locus of the point, (3 alpha+2, beta) is

I If a point (alpha, beta) lies on the circle x^2 +y^2=1 then the locus of the point (3alpha.+2, beta), is

I If a point (alpha,beta) lies on the circle x^(2)+y^(2)=1 then the locus of the point (3 alpha.+2,beta), is

Find the equation of a plane passing through the point (2,-1,5), perpendicular to the plane x+2y-3z=7 and parallel to the linne (x+5)/3=(y+1)/-1=(z-2)/1 .

Let the equation of the plane, that passes through the point (1, 4, - 3) and contains the line of intersection of the planes 3x - 2y + 4z -7 = 0 and x + 5y - 2z + 9 = 0, be alphax + betay + gammaz+3=0 , then alpha + beta + gamma is equal to :

If the straight line 2x-3y+17-0 is perpendicular to the line passing through the points (7, 17) and (15, beta) , then beta equals