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[PtBrCl(NO(2))(NH(3))] I on ionisation g...

`[PtBrCl(NO_(2))(NH_(3))]` I on ionisation gives the ion

A

`Cl^(-)`

B

`Br^(-)`

C

`I^(-) `

D

`NO_2^(-)`

Text Solution

Verified by Experts

The correct Answer is:
C
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