How is ethyl iso-propyl ether prepared ?

Explanation

Sodium isopropoxide on treating with ethyl halide gives ethyl iso-propyl ether.
`CH_(3)-underset(CH_(3))underset(|)CH-ONa+CH_(3)-underset(Cl)underset(|)CH_(2)to CH_(3)-underset(CH_(3))underset(|)CH-O-CH_(2)CH_(3)`
Alkyl halide is to be primary because with other alkyl halides, alkenes are formed.
If ethoxide and isopropyl halide are taken, elimination takes place and `CH_(3) - CH = CH_(2)` is formed.