What product is expected when tertiary butyl bromide is reacted with sodium ethoxide? Why that product is not formed and how that product can be obtained?

Explanation

`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-Br+NaOC_(2)H_(5) underset(-NaBr)to CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OC_(2)H_(5)`
The expected product is shown above. But the major product is 2-methyl-1-propene. It is because sodium ethoxide is a strong nucleophile as well as a strong base. Thus elimination reaction predominates over substitution. The above shown product in the reaction can be obtained as given below:
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-ONa+BrCH_(2)CH_(3) underset(-NaBr)to CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OC_(2)H_(5)`