Home
Class 12
CHEMISTRY
CuSO(4) +NH(4)OH gives deep blue complex...

`CuSO_(4) +NH_(4)OH` gives deep blue complex of

A

`[Cu(NH_(3))_(4)]SO_(4)`

B

`[Cu(NH_(3))_(2)]SO_(4)`

C

`[Cu(NH_(3))_(6)]SO_(4)`

D

`[Cu_(2)(NH_(3))_(4)]SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • PRACTICAL CHEMISTRY

    AAKASH SERIES|Exercise LEVEL -II (Lecture Sheet) (EXERCISE-I) (Single or more than one option correct)|38 Videos

  • PRACTICAL CHEMISTRY

    AAKASH SERIES|Exercise LEVEL -II (Lecture Sheet) (EXERCISE-II) (Linked Comprehension type questions)|9 Videos

  • POLYMERS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 4|59 Videos

  • PRINCIPLES OF METALLURGY

    AAKASH SERIES|Exercise SUBJECTIVE EXERCISE-2 (LONG ANSWER QUESTIONS )|7 Videos

Similar Questions

Explore conceptually related problems

For a general reaction given below, the value of solubility product can be given us {:(A_(x)B_(y),=xA^(+y),+yB^(-x)),(a,0,0),(a-s,xs,ys):} K_(sp)=(xs)^(x).(ys)^(y) (or) K_(sp)=x^(x)y^(y) (S)^(x+y) Solubility product gives us not only an idea about the solubility of an electrolyte in a solvent but also helps in explaining concept of precipitation and calculation [H^(+)] ion, [OH^(-) ] ion. It is also useful in qualitative analysis for the idetification and separation of basic radicals What is the molar solubility of Cu(OH)_(2) , in 1.0 M NH_(3) if the deep blue complex ion [Cu(NH_(3))_(4)]^(2+) is formed. The K_(sp), of Cu(OH)_(2) , is 1.6xx 10^(-19) and K_(3) , of [Cu(NH_(3))_(4) is 1.1 xx 10^(13)

CuSO_(4). 5H_(2)O has pale blue colour while ZnSO_(4), 7h_(2)O is white. Discuss.

CuSO_(4).5H_(2)O is blue in colour where as anhydrous CuSO_(4) is colourless. Why?

A solution is prepared by mixing 100 ml of 0.1 M NH_(4) OH and 200 ml of 0.2 M NH_(4) Cl . pK_(b) of NH_(4) OH is 4.8 . Then the pH of the solution is

A metal sulphide (A) gives (B) gas with rotten egg and (C) a colourless sulphates, when treated with dil. H_(2)SO_(4) (B) reacts with K_(2)Cr_(2)O_(7)//H^(+) to form (D) a white grey element. (D) burns in oxygen to yield (E) a colourless gas. If (B) is added in (E), it gives (D) and colourless liquid, which turns anhydrous CuSO_(4) blue. (C) gives a precipitate with NH_(3(aq)) or NaOH which dissolves in excess of NaOH. B is

A metal sulphide (A) gives (B) gas with rotten egg and (C) a colourless sulphates, when treated with dil. H_(2)SO_(4) (B) reacts with K_(2)Cr_(2)O_(7)//H^(+) to form (D) a white grey element. (D) burns in oxygen to yield (E) a colourless gas. If (B) is added in (E), it gives (D) and colourless liquid, which turns anhydrous CuSO_(4) blue. (C) gives a precipitate with NH_(3(aq)) or NaOH which dissolves in excess of NaOH. C is

A metal sulphide (A) gives (B) gas with rotten egg and (C) a colourless sulphates, when treated with dil. H_(2)SO_(4) (B) reacts with K_(2)Cr_(2)O_(7)//H^(+) to form (D) a white grey element. (D) burns in oxygen to yield (E) a colourless gas. If (B) is added in (E), it gives (D) and colourless liquid, which turns anhydrous CuSO_(4) blue. (C) gives a precipitate with NH_(3(aq)) or NaOH which dissolves in excess of NaOH. E is

In the following pair find the pair in which first compound do not form complex with NH_(3) and second give coloured complex with NH_(3)

The solution of a chemical compound reacts with AgNO_(3) solution to from a white precipitate of Y which dissolves in NH_(4)OH to give a complex Z. When Z is treated with dilute HNO_(3) , Y reappears. The chemical compound X can be: