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Compound 'A' (C(10)H(12)O) evolves H(2) ...

Compound 'A' `(C_(10)H_(12)O)` evolves `H_(2)` gas with Na metal. It reacts with `Br_(2) // C CI_(4)` to give `B( C_(10)H_(12)Br_(2)O)` with `I_(2)//NaOH` it forms iodoform and acid `C[C_(9)H_(8)O_(2)]`. A has geometrical and optical isomers. The structure of A and C should be.

A

B

Ph. CH=CHCOOH

C

D

Text Solution

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The correct Answer is:
B, C, D
Compound A (`C_(10)H_(12)O`) -OH groups reacts with Na to liberate `H_(2)`
C = C and `C -= C` groups decolourise `Br_(2) // C Cl_(4)`, `A=C_(6)H_(5)-CH=CH-overset(OH)overset(|)CH-CH_(3)` Compound `C(C_(9)H_(8)O_(2))`, `A overset(I_(2)+NaOH)to Ph-CH=CH-COOH+CHI_(3)`
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AAKASH SERIES-PRACTICAL CHEMISTRY-LEVEL -II (Lecture Sheet) (EXERCISE-I) (Single or more than one option correct)
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  9. Which of the following cations do (does) not give borax bead test?

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  12. On reaction with dil. H(2)SO(4) which of the following salts will give...

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  15. Which of the following ions can be separated by using dil. HCI?

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  16. Which of the following ions can be separated by using NH(4)CI and NH(4...

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  18. In which of the following cases will a violet colouration be observed?

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