A white sublimable solid, when boiled with a NaOH solution, give a colour less gas thal turns Nessler's Teagent brown. The solid on being heated with solid `K_(2)Cr_(2)O_(7)` and conc. `H_(2)SO_(4)`, gives red brown vapours. The white solid can be

Options

A. `NH_(4)Cl`
B. `NH_(4)Br`
C. `NH_(4)I`
D. `(NH_(4))_(2)SO_(4)`

Answer

A, B

Explanation

`NH_(4)Cl, NH_(4)Br` gives `NH_(3)` gas with NaOH turns. Nesslers reagent brown.
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)` with `Cl^(-)` gives `CrO_(2)Cl_(2)` and with `Br^(-)` gives `Br_(2)` both are red