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The correct Answer is:
A-p; B-q; C-r; D-s

A) `Cl^(-)+AgNO_(3) overset(HNO_(3))to underset("White ppt")(AgCl darr +NO_(3)^(-))`
B) `Na_(2)[Fe(CN)_(5)(NO)]+Na_(2)S to Na_(4)[Fe(CN)_(5)(NOS)]`
C) Prussian bluetest with `FeSO_(4)//FeCl_(3)`
D) `Fe^(3+)+SCN^(-) to [Fe(SCN)]^(2+)`
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