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In Kjeldahl's method 0.12 g of organic s...

In Kjeldahl's method 0.12 g of organic substance liberated ammonia. It is absorbed in 40ml of 0.05N acid. Which is neutralised by 27.5 ml of 0.05 N base. Calculate the percentage of nitrogen in the given compound.

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The correct Answer is:
7
`(NV)_(NH_(3))=(NV)_(H_(2)SO_(4))-(NV)_(NaOH)=(0.05 xx 40)-(0.05 xx 27.5)`
`(NV)_(NH_(3))=2-1.375=0.625(meq NH_(3))` `N%=(1.4(NV))/(W_("org"))=(1.4 xx 0.625)/(0.12)=7.3`
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