An aqueous solution of a white salt A gives a white precipitate B on treatment with dilute HCI in cold conditions. B is soluble in boiling water. An aqueous solution of A gives a yellow precipitate on treatment with a solution of `K_(2)CrO_(4)`. The soda extract of A is acidified with dilute `H_(2)SO_(4)` boiled to remove `CO_(2)` and treated with a freshly prepared solution of `FeSO_(4)` Concentrated `H_(2)SO_(4)` is added to the resulting solution (along the walls of the test tube so that the `H_(2)SO_(4)` forms a separate layer). A brown ring is formed at the junction of the two layers.
On treatment with a Kl solution, an aqueous solution of A will give

Options

A. a white precipitate soluble in an excess of `NH_(3)`
B. a white precipitate soluble in an excess of `NH_(3)`
C. a grey precipitate soluble in an excess of `NH_(3)`
D. a grey precipitate insoluble in an excess of `NH_(3)`

Answer

B

Explanation

A white precipitate soluble in excess of `NH_(3)`