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0.5 gm of an organic substance containin...

0.5 gm of an organic substance containing phosphorous was heated with conc. `HNO_(3)` in the Carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture (`MgNH_(4)PO_(4)`) which on ignition gave a residue of 1.0 gm of magnesium pyrophosphate (`Mg_(2)P_(2)O_(7)`). The percentage of phosphorous in the organic compound is :

A

0.5585

B

0.2972

C

0.1918

D

0.205

Text Solution

Verified by Experts

The correct Answer is:
A
`%P=(62)/(222) xx ("x mass of" Mg_(2)P_(2)O_(7) xx 100)/("mass of organic compound")=(62)/(222) xx (1 xx 100)/(0.5)=55.85 %`
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