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0.16 gm of organic acid required 25 ml o...

0.16 gm of organic acid required 25 ml of `(N)/(10)` NaOH for complete neutralization. (M. wt of acids is 128). Then the basicity of acid is

Text Solution

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The correct Answer is:
2
Equivalent acid = Equivalent of NaOH
`(wt)/("Gewt")= 25 xx 0.1 xx 10^(-3)`
`(0.16)/("Gewt") = 25 xx 0.1 xx 10^(-3)`
valancy(basicety) = `("Mol.wt")/("Gewt")=2`
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